an 8kg dog is sliding to the right on a frozen pond at 5m/s. suddenly, at the same moment, roy begins pushing the dog to the left and sally pushes the dog to the right.both roy and sally use a force of 16n and there is no friction. a)what is the net force on the dog? b)what is the dog acceleration? c)what will the dog's acceleration? c)what will the dog's velocity be after 4 second of both kids pushing him?
a) F = 16 - 16 = 0
b) F/m = 0
c) This looks like the same question as b
d) 5 m/s (unchanged)
To answer these questions, we'll need to apply Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = m * a). Additionally, we can use the equation for calculating acceleration, which is given by a = F / m.
a) Net force on the dog:
The net force acting on the dog is the sum of the two forces acting on it. In this case, since one force is acting to the left and the other to the right, we need to subtract the force to the left from the force to the right:
Net force = Force to the right - Force to the left
Given:
Force to the right = 16 N (Sally's force)
Force to the left = 16 N (Roy's force)
Net force = 16 N - 16 N = 0 N
So, the net force on the dog is 0 N.
b) Dog's acceleration:
Using the equation a = F / m, we can determine the dog's acceleration. We already know the net force acting on the dog is 0 N, and the mass of the dog is 8 kg.
Acceleration = 0 N / 8 kg = 0 m/s^2
Therefore, the dog's acceleration is 0 m/s^2.
c) What will the dog's acceleration be?
Since the net force on the dog is 0 N, the dog's acceleration will continue to be 0 m/s^2. In other words, the dog will remain at a constant velocity and not change its speed or direction.
c) What will the dog's velocity be after 4 seconds of both kids pushing him?
Since the acceleration is 0 m/s^2, the dog's velocity will not change. Therefore, the dog's velocity will be the same as its initial velocity of 5 m/s after 4 seconds of both kids pushing him.