The current in a lightning bolt is 1.6 105 A. How many coulombs of charge pass through a cross-sectional area of the lightning bolt in 0.70 s?
I don't know how to set this up???
Since one ampere is, by definition, one Coulomb per second, just multiply 160,000 by 0.7.
You should use an ^ before your exponents, as in
1.6*10^5 A
thanks! i got it
To determine the coulombs of charge that pass through a cross-sectional area of the lightning bolt, you need to use the formula:
Q = I * t
where Q is the charge in coulombs, I is the current in amperes, and t is the time in seconds.
In this case, the current (I) is given as 1.6 * 10^5 A, and the time (t) is given as 0.70 s.
Plug these values into the formula:
Q = (1.6 * 10^5 A) * (0.70 s)
Q = 1.12 * 10^5 C
So, the number of coulombs of charge that pass through the cross-sectional area of the lightning bolt in 0.70 s is 1.12 * 10^5 C.
To solve this problem, you will need to use the equation: Q = I * t, where Q is the charge in coulombs, I is the current in amperes, and t is the time in seconds.
Given:
Current (I) = 1.6 * 10^5 A
Time (t) = 0.70 s
To find the charge (Q), substitute the given values into the equation Q = I * t:
Q = (1.6 * 10^5 A) * (0.70 s)
Now, you can calculate the value of Q by multiplying the current and time:
Q = 1.12 * 10^5 C
Therefore, 1.12 * 10^5 coulombs of charge pass through a cross-sectional area of the lightning bolt in 0.70 seconds.