Posted by emmie on Tuesday, May 15, 2012 at 9:39pm.
The board applies a normal force to the barn door. Its magnitude can be obtained by setting the magnitude of the torque abouut the ground support point equal to zero.
You don't say if the 44 degree angle is with respect to the grounmd or the door. I will assume the ground. In that case,
62*g*L*cos44 = F*L*sin44
F = 62*g*cot44 = 62.9 N
At the same distance from the hinge (i.e., "the edge"), the force on the pooposite side that is necessary to move the door is equal to F.
the answer was 310 N . Do you know why ?
I get 629 N, having misread the exponent of 10 last time. I cannot explain the discrepancy with 310 N. Changing the 44 degree reference from horizontal to vertical changes cotangent to tangent does not make a large difference.
Note that L is the length of the board, which cancels out
The weight force of the board is applied at the middle, if it is uniform.
Then
62 g (L/2) cos44 = F L sin44
F = 31 g cot44 = 314.6 N
They may be rounding to 310 because there are only two siginificant figures in the input data.
I forgot the 1/2 factor in my first answer
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