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trig

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solve for the equation x

sin x= -.35
180<x<270

sin x= .2
90<x<180

cos x = -.72
180< x<270


please explain, thanks :)

  • trig -

    Here is a standard way to solve these kind of problems, I will do the first one

    sinx = -.35 , 180 < x <270

    1. Find the acute angle, sometimes called the "angle in standard position"
    by using the positive decimal
    if sinx = .35, x = 20.5°

    but x is supposed to be in III , then
    x = 180 + 20.5 = 200.5°

    check: on calculator, sin 200.5 = -.3502..

    try the others the same way, check the answer with your calculator.

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