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August 29, 2014

August 29, 2014

Posted by **bkue** on Tuesday, May 15, 2012 at 8:40pm.

sin x= -.35

180<x<270

sin x= .2

90<x<180

cos x = -.72

180< x<270

please explain, thanks :)

- trig -
**Reiny**, Tuesday, May 15, 2012 at 9:27pmHere is a standard way to solve these kind of problems, I will do the first one

sinx = -.35 , 180 < x <270

1. Find the acute angle, sometimes called the "angle in standard position"

by using the positive decimal

if sinx = .35, x = 20.5°

but x is supposed to be in III , then

x = 180 + 20.5 = 200.5°

check: on calculator, sin 200.5 = -.3502..

try the others the same way, check the answer with your calculator.

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