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February 1, 2015

February 1, 2015

Posted by **shirlee** on Tuesday, May 15, 2012 at 6:38pm.

find f'(x)=0

So first derivative:

f'(x)=16x^3-6x^2-70x+36

0 = 16x^3-6x^2-70x+36

Ok.. I know I should factor it somewhere.. I just couldn't see where..

Thanks!

- calculus -
**MathMate**, Tuesday, May 15, 2012 at 9:43pmf'(x) should read:

16x^3-12x^2-70x+36

and f'(-2)=0

From there, you can find the other factors.

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