Posted by **:)** on Tuesday, May 15, 2012 at 8:19am.

A spherical balloon is being inflated so that its volume is increasing at the rate of 5 cubic meter per minute.At what rate is the radius increasing when the radius is 6 meters?

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**Damon**, Tuesday, May 15, 2012 at 8:30am
V = (4/3) pi r^3

dV/dt = 4 pi r^2 dr/dt = surface area * dr/dt of course

so

dr/dt = dV/dt /(4 pi r^2)

= 5/(100 pi ) = 1/(20 pi)

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**:)**, Tuesday, May 15, 2012 at 9:14am
thank you so much! :)

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**:)**, Tuesday, May 15, 2012 at 9:25am
uhm, just one more thing. Isn't it 5/144π ? :)

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**Damon**, Tuesday, May 15, 2012 at 10:04am
yes, right, forgot 6 and not 5

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**:)**, Tuesday, May 15, 2012 at 7:48pm
thank you. :) you really did a big help. Godbless

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