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July 30, 2014

July 30, 2014

Posted by **Bobert** on Monday, May 14, 2012 at 11:23pm.

- pre-calc -
**Reiny**, Monday, May 14, 2012 at 11:49pmmake a sketch to create the right-angled triangle OAB, where A is the 90° angle

tanØ = 3/2, where Ø is the angle O

Ø = 56.3°

So to head back he should take the course

S 11.3° E

or

a bearing of 168.7°

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