y = 5x^3 - 9 then we interchange x and y: x = 5y^3 - 9 and we solve for y: x + 9 = 5y^3 (x + 9)/5 = y^3 y = [(x + 9)/5]^(1/3) then finally we substitute y for f'(x): f'(x) = [(x + 9)/5]^(1/3) hope this helps~ :)
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