perimeter of rectangular is 32 in .what are the length and width that will give the rectangle the largest possible area 4in,x12in. 5in.x11 in. ,7in. x9in. ,8in x8in. i answered 8x8
8x8
To find the dimensions that will give the rectangle the largest possible area, we need to consider the formula for the perimeter and area of a rectangle.
Let's first calculate the perimeter using the formula P = 2(l + w), where P represents the perimeter, l represents the length, and w represents the width.
For the options given:
1. 4 in x 12 in: P = 2(4 + 12) = 2(16) = 32 in
2. 5 in x 11 in: P = 2(5 + 11) = 2(16) = 32 in
3. 7 in x 9 in: P = 2(7 + 9) = 2(16) = 32 in
4. 8 in x 8 in: P = 2(8 + 8) = 2(16) = 32 in
As you can see, all four options have the same perimeter of 32 inches. However, we need to find the dimensions that will give us the largest possible area.
The formula for the area of a rectangle is A = l x w, where A represents the area, l represents the length, and w represents the width.
Now, let's calculate the areas for each option:
1. 4 in x 12 in: A = 4 x 12 = 48 square inches
2. 5 in x 11 in: A = 5 x 11 = 55 square inches
3. 7 in x 9 in: A = 7 x 9 = 63 square inches
4. 8 in x 8 in: A = 8 x 8 = 64 square inches
From the calculations, we can see that the dimensions of 8 inches by 8 inches will indeed give us the largest possible area, which is 64 square inches.
Therefore, your answer of 8 in by 8 in is correct.