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March 30, 2017

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The operating potential difference of a light bulb is 120 V. The power rating of the bulb is 105 W. Find the current in the bulb and the bulb's resistance.
Current
1 A
Resistance
2

I got 0.916 for A
and 115 for B but they are wrong

  • physics - ,

    P=I•U ,
    I =P/U =105/120 =0.875 A
    P =I²•R,
    R=P/I² =105/120²=7.3•10^-3 Ω

  • physics - ,

    the second answer is supposed to be in the hundreds

  • physics - ,

    7.3•10^-3 = 0.0073

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