The operating potential difference of a light bulb is 120 V. The power rating of the bulb is 105 W. Find the current in the bulb and the bulb's resistance.
I got 0.916 for A
and 115 for B but they are wrong
I =P/U =105/120 =0.875 A
R=P/I² =105/120²=7.3•10^-3 Ω
the second answer is supposed to be in the hundreds
7.3•10^-3 = 0.0073