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Posted by Amelia on Monday, May 14, 2012 at 9:13am.

The operating potential difference of a light bulb is 120 V. The power rating of the bulb is 105 W. Find the current in the bulb and the bulb's resistance. Current 1 A Resistance 2 I got 0.916 for A and 115 for B but they are wrong

P=I•U , I =P/U =105/120 =0.875 A P =I²•R, R=P/I² =105/120²=7.3•10^-3 Ω

the second answer is supposed to be in the hundreds

7.3•10^-3 = 0.0073

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