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April 21, 2015

April 21, 2015

Posted by **loraine** on Monday, May 14, 2012 at 12:17am.

a)7 zebra, 6 neon

b)8 zebra, 5 neon

c)6 zebra, 7 neon

d)5 zebra, 8 neon

- algebra 1A -
**Henry**, Tuesday, May 15, 2012 at 8:55pmX Zebra fish.

Y Neon fish.

Eq1: X + Y = 13.

Eq2: 2.1X + 1.8y = 25.80

Multiply Eq1 by -2.1:

-2.1x - 2.1y = -27.3

2.1x + 1.8y = 25.8

Add the Eqs:

-0.3y = -1.5

Y = -1.5 / -0.3 = 5 = Neon.

X + 5 = 13

X = 8 Zebras.

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