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Chemistry

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A weak acid solution, HX 0.37 M, has a pH of 3.70. Calculate the acidity constant for this acid.

  • Chemistry - ,

    pH = -log(H^+)
    3.70 = -log(H^+)
    Convert that; I get about 2E=4 but you need to confirm that.
    ...........HX ==> H^+ + X^-
    I.........0.37....0......0
    C........-2E-4...2E-4...2E-4
    E......0.37-2E-4..2E-4...2E-4

    Substitute into the Ka expression and solve for Ka.

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