Posted by **ct** on Sunday, May 13, 2012 at 9:15pm.

Eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve.

x=4+2cos(theta) y=-1+2sin(theta)

- calculus -
**Steve**, Monday, May 14, 2012 at 9:55am
cosθ = (x-4)/2

sinθ = (y+1)/2

(x-4)^2 + (y+1)^2 = 4

it's easy to see why this drops out if you rewrite the original equations as

(x-4) = 2cosθ

(y+1) = 2sinθ

So, it's the regular equation for a circle, but centered at (4,-1) instead of (0,0)

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