If a basketball has a circumference of C = 2.98 ft, what is its surface area and its volume?
http://math.about.com/od/formulas/ss/surfaceareavol.htm
I got surface area = 27.9
And the volume is 4.80
Is that right if I'm suppose to round to the nearest 10th?
Mike -- why are you interfering with Gretchen's question? Are you trying to help her with it?
To find the surface area of a basketball, we can use the formula:
Surface Area = 4πr^2
where π is a mathematical constant approximately equal to 3.14159 and r is the radius of the basketball.
To find the radius, we can use the formula:
Circumference = 2πr
Given that the circumference C is 2.98 ft, we can rearrange the formula to solve for r:
C = 2πr
2.98 = 2πr
Divide both sides by 2π:
r = 2.98 / (2π)
Now we have the radius, so we can calculate the surface area:
Surface Area = 4πr^2
Surface Area = 4π(2.98 / (2π))^2
Simplifying the equation:
Surface Area = 4π(2.98 / (2π))^2
Surface Area = 4(2.98 / (2π))^2
Surface Area = 4(2.98^2 / (2π)^2)
Now we can calculate the surface area using the given formula:
Surface Area ≈ 4(2.98^2 / (2π)^2)
To find the volume of a basketball, we can use the formula:
Volume = (4/3)πr^3
Using the same value of the radius r that we found earlier:
Volume = (4/3)π(2.98 / (2π))^3
Volume = (4/3)π(2.98^3 / (2π)^3)
Now we can calculate the volume using the given formula:
Volume ≈ (4/3)π(2.98^3 / (2π)^3)
Calculating the values of the surface area and volume would yield the final result.