Posted by trig identities on Sunday, May 13, 2012 at 8:16pm.
cosx secx=1
cos^2 *csc^2= ctn^2 x
1+ctn^2=csc^2
multipy left by sin^2/sin^2
1/sin^2 (sin^2+cos^2)=
csc^2 = csc^2
Related Questions
math - i have a few questions cosx + cosx =2secx ----- ----- 1+sinx 1-sinx cos(x...
trig 26 - simplify to a constant or trig func. 1. sec ²u-tan ²u/cos &...
math - How would you establish this identity: (1+sec(beta))/(sec(beta))=(sin^2(...
pre-calc help !!!!!!! - #1 cos x+sec x=2 #2 (1+tan x)^2= 2 tan x+2 #3 cos^2x-sin...
trig - How do you solve csc2x + 1 = 0
trig - I need HELP Verify the identity Cot3X/CSCX=cosX(csc2X-1)
pre calc - The terminal side of an angle in standard position goes through the ...
Trig - Solve in terms of sine and cosine: sec(x) csc(x)- sec(x) sin(x) so far I ...
Pre Calc - sec(cos-1 (4/5))=?
pre calc trig check my work please - sin x + cos x -------------- = ? sin x sin ...
For Further Reading
