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chemistry

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a 8.6 *10 to the -3 power M solution of H3PO4 has a PH of 2.30 what is the Ka for H3PO4?

  • chemistry - ,

    Convert pH to (H^+). That's approximately 5E-3.
    ............H3PO4 ==> H^+ + H2PO4^-
    I.........0.0086 M....0.......0
    C...........-x........x........x
    E.....0.0086-x........x........x
    The problem tells you x = (H^+) = (approximately) 5E-3
    Plug that in for x (into the Ka expression) and solve for Ka.

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