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If 33.7 ml of 0.210 M KOH is required to completely neutralize 27.0 ml of a HC2H3O2 solution, what is the molarity of the acetic acid solution?

HC2H3O2(aq)+ KOH(aq)-->KC2H3O2(aq)+H2O(l)


    mols KOH = M x L = ?
    mols acetic acid = mols KOH (from the coefficients in the balanced equation.)
    M acid = mols acid/L acid. You know mols and L, solve for M.

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