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November 28, 2014

November 28, 2014

Posted by **someone** on Saturday, May 12, 2012 at 5:20pm.

n(t)=1710e071t

(a) The initial number of bacteria is

(b) The relative rate of growth of this bacterium population is

(c) The number of bacteria after 3 hours is

(d) After how many hours will the number of bacteria reach 10,000?

Your answer is

I got the A=1710

B=?

c=14389

D=?

I keep getting b and d wrong any suggestions. thanks in advance!

- math -
**Henry**, Sunday, May 13, 2012 at 8:43pma. ok.

b.

c. ok.

d. 1710*e^0.71t = 10,000

e^0.71t = 10,000 / 1710 = 5.85

0.71t*Lne = Ln5.85

Divide both sides by Lne:

0.71t = Ln5.85 / Lne = 1.7664

t = 1.7664 / 0.71 = 2.49 Hours.

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