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March 24, 2017

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Determine the pressure in atm for a 10 g of CO2 sample contained in a sealed 10 L tank at 50degrees C?

Did anyone get 26.5 atm?

  • CHEMISTRY - ,

    p =m•R•T/μ•V = =10•10^-3•8.31•323/44•10•10^-3 = 61 Pa = =6.02•10^4 atm.

  • CHEMISTRY - ,

    I get 61. But after that then what?

  • CHEMISTRY - ,

    I have something completely different.
    V must go in in L.
    P = nRT/V
    n = mol = g/molar mass = 10/44.
    P 10*0.o08206*(273+50)/10 = 0.60 atm.

  • CHEMISTRY - ,

    Of course,
    1 Pa = 9.869•10^-6 atm,

    61 Pa = 6.02•10 ^ - 4 atm.

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