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April 16, 2014

April 16, 2014

Posted by **Filip** on Saturday, May 12, 2012 at 6:20am.

- Physics -
**drwls**, Saturday, May 12, 2012 at 7:10amThe initial distance between the particles is

Sqrt(9 + 16 +64) = sqrt89 = R1

The final distance between the particles is

Sqrt(25 +196 +4) = sqrt225 = 15 = R2

Calculate the change in potential energy

K Q1 Q2 (1/R1 - 1/R2)

K is the Coulomb constant

You need to state the units for position. Is it meters?

- Physics -
**Filip**, Saturday, May 12, 2012 at 8:40amI need to calculate this using the integral formula which is: W = - ∫ F dl = - q ∫ E dl

Where E = 1 / 4piε0 * R(vector) / R^3

I am just confused in what E-field I have to use and do I need to calculate X,Y & Z separately??

- Physics -
**Filip**, Saturday, May 12, 2012 at 8:42amAnd regarding the position of the charges it only says its positions in the room for example charge 1 is : (x,y,z) = (2,-3,8). But it should be in Meters if SI-unit is needed..

- Physics -
**drwls**, Saturday, May 12, 2012 at 10:02amThe method I described is a shortcut that will give the correct answer. If you are going to use F*dl integrals, you have to specify the path the moviong charge follows, not just the end points. Ultimately, the answer only depends upon how much the distance between the charges changes, and the productof the two charges.

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