Which is the standard form of the equation with p = 26, O=3pi/4 ?
the O before the =3pi has a diagonal slash through it.
You have written two equations that seem to describe two polar coordinates. Is "p" the radisl distance from the origin?
It is not clear what you mean by "standard form"
To determine the standard form of the equation given p = 26 and O = 3π/4 (with a slashed O), we need to use relevant mathematical concepts.
First, let's clarify the variables involved:
- p represents the parameter or the distance from the origin to a point on a polar curve.
- θ (usually denoted by a theta symbol, but here represented as O with a diagonal slash) represents the angle formed between the positive x-axis and the line segment from the origin to the point on the curve.
In polar coordinates, the standard form of an equation is usually written as r = f(θ), where r is the distance from the origin (polar radius) and θ is the angle measured in radians.
In this case, we are given p = 26 and O = 3π/4 (with a slashed O). Since p represents the polar radius, we can immediately substitute it into our equation as follows:
r = p
So, the equation in polar coordinates is:
r = 26
However, if you meant to convert this equation into rectangular (Cartesian) form, where x and y are the variables, we can use the following trigonometric relationships:
x = r * cos(θ)
y = r * sin(θ)
Substituting r = 26 into these equations, we get:
x = 26 * cos(θ)
y = 26 * sin(θ)
These equations represent the rectangular form of the equation, given p = 26 and O = 3π/4 (with a slashed O).