Posted by **Ana** on Friday, May 11, 2012 at 10:14pm.

If two number cubes are tossed, what is the probability of getting a sum that is less than 6, given that 1 number cube shows a 3 ?

- Math -
**MathMate**, Friday, May 11, 2012 at 10:34pm
Assuming 6-sided number cubes.

Let the events

A=throwing less than 6

B=one of them is a three

Then P(A∩B)

=|{(1,3),(2,3),(3,1),(3,2)}| / 36

= 1/9

P(B)

=2/6

=1/3

Throwing less than six given one of them is a 3 is therefore the conditional probability of A given B, or

P(A|B)

=P(A∩B)/P(B)

=(1/9) /(1/3)

=1/3

- Math -
**Cupcake**, Monday, April 11, 2016 at 1:07pm
I have a different one so i dont know this one sorry!!

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