Math
posted by Ana .
If two number cubes are tossed, what is the probability of getting a sum that is less than 6, given that 1 number cube shows a 3 ?

Assuming 6sided number cubes.
Let the events
A=throwing less than 6
B=one of them is a three
Then P(A∩B)
={(1,3),(2,3),(3,1),(3,2)} / 36
= 1/9
P(B)
=2/6
=1/3
Throwing less than six given one of them is a 3 is therefore the conditional probability of A given B, or
P(AB)
=P(A∩B)/P(B)
=(1/9) /(1/3)
=1/3 
I have a different one so i don't know this one sorry!!