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Math

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If two number cubes are tossed, what is the probability of getting a sum that is less than 6, given that 1 number cube shows a 3 ?

  • Math -

    Assuming 6-sided number cubes.

    Let the events
    A=throwing less than 6
    B=one of them is a three

    Then P(A∩B)
    =|{(1,3),(2,3),(3,1),(3,2)}| / 36
    = 1/9

    P(B)
    =2/6
    =1/3

    Throwing less than six given one of them is a 3 is therefore the conditional probability of A given B, or
    P(A|B)
    =P(A∩B)/P(B)
    =(1/9) /(1/3)
    =1/3

  • Math -

    I have a different one so i don't know this one sorry!!

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