A bag of hard candy contains 8 cherry candies, 6 grape candies, 7 pineapple candies, and 4 lime candies. Juan takes one candy from the bag without looking. What is the probability that he chooses a cherry candy?
8/(8+6+7+4) = ?
.32
To determine the probability that Juan chooses a cherry candy, we need to know the total number of candies in the bag, as well as the number of cherry candies.
The total number of candies in the bag is the sum of the number of cherry candies, grape candies, pineapple candies, and lime candies:
Total candies = 8 (cherry) + 6 (grape) + 7 (pineapple) + 4 (lime) = 25
The number of cherry candies is given as 8.
Now, we can calculate the probability:
Probability of choosing a cherry candy = Number of cherry candies / Total number of candies
Probability of choosing a cherry candy = 8 / 25
Therefore, the probability that Juan chooses a cherry candy is 8/25 or 0.32 (rounded to two decimal places), which can also be expressed as 32%.