A 330- piano slides 3.8 down a 23 incline and is kept from accelerating by a man who is pushing back on it parallel to the incline.

a.Determine the work done by the force of gravity.
b.Determine the work done by the man on the piano.

you need to add units to the measurements. Ill assume the following: 330 kilograms, 3.8 meters, 23 degrees.

mass*gravity*amount of gravity working=
330*9.8*cos(90-23)=force or work of gravity

if the man fights gravity the entire time then his force is equal and opposite to gravity.

To determine the work done by the force of gravity, you need to calculate the gravitational potential energy of the piano. The formula for gravitational potential energy is given by:

Gravitational Potential Energy = mgh

Where:
m = mass of the piano (330 kg)
g = acceleration due to gravity (approximately 9.8 m/s^2)
h = height or vertical distance traveled by the piano down the incline (3.8 m)

a. Calculating the work done by the force of gravity:

Gravitational Potential Energy = (mass) x (acceleration due to gravity) x (height)
= (330 kg) x (9.8 m/s^2) x (3.8 m)
= 12107.2 Joules

Therefore, the work done by the force of gravity is 12107.2 Joules.

Now, let's move on to determining the work done by the man on the piano.

b. The work done by the man on the piano is given by the formula:

Work Done = Force applied x Distance moved in the direction of the force

In this case, the man is pushing parallel to the incline, which means the force applied is parallel to the direction of motion of the piano. Therefore, the work done by the man is equal to the force applied multiplied by the distance the piano moves parallel to the incline.

Since the piano is kept from accelerating, the force applied by the man is equal in magnitude and opposite in direction to the force due to gravity. So the net force acting on the piano is zero.

Hence, the work done by the man on the piano is zero.