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March 27, 2017

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4x^2+y^2-48x-4y+48=0 what is the distance from c to foci of this equation
The center is (6,2)
major is 10 i think
and minor is 5 but they might be wrong

  • Ellipses Part 2:) - ,

    4x^2+y^2-48x-4y+48=0
    4(x^2 - 12x) + (y^2 - 4y) = -48
    4(x^2 - 12x + 36) + (y^2 - 4y + 4) = -48 + 144 + 4
    4(x-6)^2 + (y-2)^2 = 100

    (x-6)^2/25 + (y-2)^2/100 = 1

    You are correct, although
    semi-major is 10
    semi-minor is 5

    c^2 = 100 - 25
    c = sqrt(75) = 5*sqrt(3)

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