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Chemistry

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A system is represented by the following equation:
2A(aq) + B(aq) --> 3C(aq)

At equilibrium, [C]=0.6 M. Calculate the value of K if initially 1 mol of A and 2 mol of B were placed in a 1 L flask.

  • Chemistry -

    we will assume that the aqueous solutions fill the 1 L flask.

    At start

    1 mol A + 2 mol B and 0 mol C

    At equilibrium

    1-2x mol of A and 2-x mol of B and 3x mol of C

    so x=0.2 M

    K=x^3/(1-2x)^2(2-x)

    K=(0.2)^3/(0.6)^2(1.8)

    K=0.008/(0.36)(1.8)

    K=0.012 (with no units)

  • Chemistry -

    I am having trouble with this question so I decided to check online. The question sheet in which I got this question from came with an answer sheet, and it says the answer for k = 0.33. Another online source gave an answer of 0.024. I'm not sure what values are needed in the change row.

    2A + B <----> 3C
    INITIAL 1 2 0
    CHANGE +3X
    EQUILIBRIUM 0.6 M

    If 0.6 = 3x, x should equal 0.2? How is x affecting A + B?

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