Chemistry
posted by Sandra .
A system is represented by the following equation:
2A(aq) + B(aq) > 3C(aq)
At equilibrium, [C]=0.6 M. Calculate the value of K if initially 1 mol of A and 2 mol of B were placed in a 1 L flask.

we will assume that the aqueous solutions fill the 1 L flask.
At start
1 mol A + 2 mol B and 0 mol C
At equilibrium
12x mol of A and 2x mol of B and 3x mol of C
so x=0.2 M
K=x^3/(12x)^2(2x)
K=(0.2)^3/(0.6)^2(1.8)
K=0.008/(0.36)(1.8)
K=0.012 (with no units) 
I am having trouble with this question so I decided to check online. The question sheet in which I got this question from came with an answer sheet, and it says the answer for k = 0.33. Another online source gave an answer of 0.024. I'm not sure what values are needed in the change row.
2A + B <> 3C
INITIAL 1 2 0
CHANGE +3X
EQUILIBRIUM 0.6 M
If 0.6 = 3x, x should equal 0.2? How is x affecting A + B?