Posted by Sandra on Friday, May 11, 2012 at 1:32am.
........A2B3 ==> 2A + 3B
I......0.01.......0....0
C.......-x........2x...3x
E....0.01-x.......2x...3x
The problem tells us that 3x = 0.006 = mols B; therefore, x = 0.006/3 = 0.002
Equilibrium mols are as follows:
A2B3 = 0.01-0.002 = ?
A = 2*0.002 = ?
B = 0.006
These are mols. You must convert to molarity. Do that by M = mols/L. The volume is given as 0.1L. Then substitute concns into the Keq expression and solve for Kc.
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