Posted by **Sandra** on Friday, May 11, 2012 at 1:32am.

A 100 mL container is filled with 0.01 mol of A2B3. At equilibrium, it also contains 0.006 mol of B. Find the value of K.

A2B3(g) --> 2A(g) +3B(g)

- Chemistry -
**DrBob222**, Friday, May 11, 2012 at 3:51pm
........A2B3 ==> 2A + 3B

I......0.01.......0....0

C.......-x........2x...3x

E....0.01-x.......2x...3x

The problem tells us that 3x = 0.006 = mols B; therefore, x = 0.006/3 = 0.002

Equilibrium mols are as follows:

A2B3 = 0.01-0.002 = ?

A = 2*0.002 = ?

B = 0.006

These are mols. You must convert to molarity. Do that by M = mols/L. The volume is given as 0.1L. Then substitute concns into the Keq expression and solve for Kc.

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