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posted by Katie on Thursday, May 10, 2012 at 11:13pm.
You work with the following system: 2X(g) <--> Y(g) At, equilibrium, [Y]=3[X]. If K=10, calculate the [Y] at equilibrium.
K = 10 = (Y)/(X)^2 = 3X/(X)^2 = 3/X 10 = 3/X; X = 3/10 = 0.30
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