Posted by **Alica** on Thursday, May 10, 2012 at 8:45pm.

A 1.60-g bullet, moving at 542 m/s, strikes a 0.249-kg piece of wood at rest on a frictionless table. The bullet sticks in the wood, and the combined mass moves slowly down the table.

(a) Find the speed of the combination after the collision.

m/s

(b) Find the kinetic energy of the bullet before the collision.

J

(c) Find the kinetic energy of the combination after the collision.

J

(d) How much kinetic energy did the bullet lose?

J

(e) What percent of the bullet's original kinetic energy is lost?

%

- AP physics -
**Elena**, Friday, May 11, 2012 at 2:28pm
m1 = 0.0016 kg, v1 = 542 m/s, m2 =0.249, v2 = 0, u = ?

(a) m1•v1 +m2•v2 = (m1+m2) •u

u = m1•v1/(m1+m2).

(b) KE1 =m1•v1²/2.

(c) KE = ((m1+m2) •u²/2

(d) ΔKE = KE1 – KE.

(e) (ΔKE/KE1) •100%

- AP physics -
**Alica**, Friday, May 11, 2012 at 7:48pm
I have never used these equations before, can you explain/ show me

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