Posted by **Haley ** on Thursday, May 10, 2012 at 8:44pm.

An archer puts a 0.26-kg arrow to the bow-string. An average force of 200 N is exerted to draw the string back 1.4 m.

(a) Assuming no frictional loss, with what speed does the arrow leave the bow?

m/s

(b) If the arrow is shot straight up, how high does it rise?

m

I got 47 for A

and 113 for B, but neither work?

- physics -
**Elena**, Friday, May 11, 2012 at 2:20pm
Work is

W =F•x =200•1.4 =280 J,

W =KE = m•v²/2,

v =sqrt(2•W/m) = sqrt(2•280/0.26) =46.4 m/s.

KE =PE = m•g•h

h = KE/m•g = 280/0.26•9.8 ≈110 m.

- physics -
**Alica**, Friday, May 11, 2012 at 7:46pm
both of these answers

a- 280J

and

b-46.4m/s

are wrong?

- physics -
**Elena**, Saturday, May 12, 2012 at 3:55am
These answers (v=46.4 m/s, h= 109.89≈110 m) are correct.

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