Posted by **blue ivy** on Thursday, May 10, 2012 at 8:13pm.

A 0.250 kg ball is thrown straight upward with an initial velocity of 38 m/s. If air friction is ignored, calculate the:

(a) height of the ball when its speed is 12 m/s

(b) height to which the ball rises before falling

(c) How would your answers to (a) and (b) change if

you repeated the exercise with a ball twice as

massive?

- Physics -
**bobpursley**, Thursday, May 10, 2012 at 8:17pm
Use energy considerations:

a) 1/2 m vi^2=1/2 mg vf^2+mg*hfinal

b) same equation, vf=0

c) divide the equation in a) by m, and see how the mass then affects that equation.

- Phizzics.... -
**angel**, Tuesday, October 15, 2013 at 11:41am
A ball is thrown straight up from ground level. After a time 4.1 s, it passes a height of 157.1 m. What was its initial speed? The accelera-

tion due to gravity is 9.8 m/s2 . what is its initial speed

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