Posted by HELPP ! on Thursday, May 10, 2012 at 7:58pm.
CuBr ==> Cu^+ + Br^-
Cu^+ + 2NH3 ==> Cu(NH3)2^+
----------------------------
add equn 1 to eqn 2.
...CuBr(s) + 2NH3 ==>Cu(NH3)2^+ + Br^-
I.............0.81M...0............0
C............-2x......x............x
E...........0.81-2x...x............x
Keq for the rxn shown is Ksp*Kf
Substitute from the ICE chart and solve for x = [Cu(NH3)2] = (Br^-) = solubility of CuBr in M. Then convert to g/L.
milk
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