Give the slope and y-intercept of the given line.
1.2x-3y=6
2. y=-2x
3. y=3
4. x+2=0
Find the slope of the line that is a) parallel and b) perpendicular to the given line.
1. x=-8
2. y=10
1.
2 x - 3 y = 6
- 3 y = 6 - 2 x Divide both sides by - 3
y = 6 / - 3 - 2 x / - 3
y = - 2 + 2 x / 3
y = ( 2 / 3 ) x - 2
Slope 2 / 3
y - intercept
2 * 0 - 3 y = 6
- 3 y = 6 Divide both sides by - 3
y = 6 / - 3 = - 2
2.
y = - 2 x
Slope - 2
y - intercept
y = - 2 * 0 = 0
3.
y = 3
y = 3 for all value of x
This line is parallel with x axis
Slope = tan 180 ° = 0
y - intercept :
y = 3
4.
x + 2 = 0
x = - 2
x = - 2 for all value of y
This line is parallel with y axis
Slope = tan 90 ° = infinity
y - intercept not exist
1.
x = - 8
x = - 8 for all value of y
This line is parallel with y axis
Slope = tan 90 ° = infinity
a)
Parallel line slope = tan 90 ° = infinity
b)
Normal line slope = tan ( 90 ° - 90 ° ) = tan 0 = 0
2.
y = 10
y = 10 for all value of x
This line is parallel with x axis
Slope = tan 180 ° = 0
a)
Parallel line slope = tan 180 ° = 0
b)
Normal line slope = tan ( 180 ° - 90 ° ) = tan 90 ° = infinity