Wednesday

June 1, 2016
Posted by **elizabeth** on Thursday, May 10, 2012 at 2:41pm.

1.2x-3y=6

2. y=-2x

3. y=3

4. x+2=0

Find the slope of the line that is a) parallel and b) perpendicular to the given line.

1. x=-8

2. y=10

- math -
**Anonymous**, Thursday, May 10, 2012 at 4:58pm1.

2 x - 3 y = 6

- 3 y = 6 - 2 x Divide both sides by - 3

y = 6 / - 3 - 2 x / - 3

y = - 2 + 2 x / 3

y = ( 2 / 3 ) x - 2

Slope 2 / 3

y - intercept

2 * 0 - 3 y = 6

- 3 y = 6 Divide both sides by - 3

y = 6 / - 3 = - 2

2.

y = - 2 x

Slope - 2

y - intercept

y = - 2 * 0 = 0

3.

y = 3

y = 3 for all value of x

This line is parallel with x axis

Slope = tan 180 ° = 0

y - intercept :

y = 3

4.

x + 2 = 0

x = - 2

x = - 2 for all value of y

This line is parallel with y axis

Slope = tan 90 ° = infinity

y - intercept not exist

1.

x = - 8

x = - 8 for all value of y

This line is parallel with y axis

Slope = tan 90 ° = infinity

a)

Parallel line slope = tan 90 ° = infinity

b)

Normal line slope = tan ( 90 ° - 90 ° ) = tan 0 = 0

2.

y = 10

y = 10 for all value of x

This line is parallel with x axis

Slope = tan 180 ° = 0

a)

Parallel line slope = tan 180 ° = 0

b)

Normal line slope = tan ( 180 ° - 90 ° ) = tan 90 ° = infinity