posted by john on .
Suppose that 98% of your customers in your market have internet access and you select a random sample of 500 customers. What is the standard error of the proportion of customers who don’t have internet access?
I seem to be struggling with no standard deviation listed
Standard deviation = √npq = √(500 * .98 * .02) = ?
(Note: q = 1 - p)
I'll let you finish.