Posted by Piggy on .
A 30-60-90 triangle is inscribed in a circle. The length of the hypotenuse is 12 inches. If a coin is tossed on the figure, what is the probability that the coin will land in the circle, but outside the triangle?
All right-triangles inscribe in a circle with a diameter equal to the hypotenuse.
Therefore for the 30-60-90 triangle, the radius of the circle is 6 inches, and the short side is also 6 inches. The height is 6sqrt(3), so the area of the triangle is
At=36sqrt(3)/2 = 18 sqrt(3) sq.in.
The area of the circle is
The probability of falling inside the circle and outside the triangle is therefore
the quesiton is land in the circle, but outside the triangle. Is it the probability is (AC - AT)/AC
81.22/113 x 100%
P(C\T) (probability inside circle minus triangle)