Posted by **Cathy** on Wednesday, May 9, 2012 at 11:31pm.

Two children balance on opposite ends of a seesaw. One child weighs 45 pounds and the other weighs 38 pounds. The distance between them is 10 feet. What is the distance of each child from the fulcrum (the center balance point of the seesaw)? (HINT: The product of the distance from the fulcrum and the weight of the chid must be equal on both sides of the fulcrum in order to balance the seesaw.

## Answer this Question

## Related Questions

- Math - Two children sit on a seesaw that is 14 ft long. One child weighs 95 lb, ...
- algebra - To balance a seesaw, the distance, in feet, a person is from the ...
- physics - two children sit at opposite ends of a 60 lb. 10 ft. seesaw which is ...
- physics - An adult and a child are on a seesaw 14.5 ft long. The adult weighs ...
- Kinesiology - Joey weighs 77 lb and sits on a seesaw at a distance of 30 inches ...
- math - the force of gravity varies inversely as the square of the distance ...
- math - 1. Two children balance a see-saw in horizontal equilibrium. One weighs ...
- math - 1. Two children balance a see-saw in horizontal equilibrium. One weighs ...
- math - 1. Two children balance a see-saw in horizontal equilibrium. One weighs ...
- physics - Two children seat themselves on a seesaw, the one on the left has a ...