Monday
July 28, 2014

Homework Help: Algebra

Posted by Cathy on Wednesday, May 9, 2012 at 11:31pm.

Two children balance on opposite ends of a seesaw. One child weighs 45 pounds and the other weighs 38 pounds. The distance between them is 10 feet. What is the distance of each child from the fulcrum (the center balance point of the seesaw)? (HINT: The product of the distance from the fulcrum and the weight of the chid must be equal on both sides of the fulcrum in order to balance the seesaw.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

algebra - To balance a seesaw, the distance, in feet, a person is from the ...
Math - Two children sit on a seesaw that is 14 ft long. One child weighs 95 lb, ...
physics - two children sit at opposite ends of a 60 lb. 10 ft. seesaw which is ...
Kinesiology - Joey weighs 77 lb and sits on a seesaw at a distance of 30 inches ...
Math - Averages - Six dogs have an average(arithmetic mean) weight of 55 pounds...
physics - An adult and a child are on a seesaw 14.5 ft long. The adult weighs ...
physics - How much exertion in pounds does it take a woman who weighs 115 pounds...
2nd grade - mom weighs 100 pounds her son weighs 450 pounds. how many pounds do ...
math - the force of gravity varies inversely as the square of the distance ...
pre-calculus honors - Generate a function that models the situation. Consider ...

Search
Members