Posted by **Hannah** on Wednesday, May 9, 2012 at 10:41pm.

One bag contains 5 red marbles, 4 blue marbles, and 3 yellow marbles, and a second bag contains 4 red marbles, 6 blue marbles, and 5 yellow marbles. If Lydia randomly draws one marble from each bag, what is the probability that they are both not yellow?

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**MathMate**, Thursday, May 10, 2012 at 7:36am
The two draws are independent.

So the probability of getting a yellow in both bags is the product of the probability of getting a yellow in each bag.

P1(Y)=3/12

P2(Y)=5/15

So

P(Y,Y)=P1(Y)*P2(Y)

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**Anonymous**, Saturday, May 12, 2012 at 9:52am
ryrrr7o

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**Anonymous**, Wednesday, March 20, 2013 at 9:44pm
1/12

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**stephani**, Wednesday, May 21, 2014 at 9:59pm
4

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**Andrew**, Tuesday, May 27, 2014 at 3:48pm
The question asks the opposite... not yellow.

so 9/12 * 10/15 = .75 * .666 = 50%

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**Marty Murray**, Sunday, July 6, 2014 at 9:56am
Andrew has it right.

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