factor the expression given below 9x^2-16

Try using the standard form:

a^2-b^2=(a+b)(a-b)
and noting that
9x^2-16 = (3x)^2 - 4^2

To factor the expression 9x^2-16, we can use a method called the difference of squares.

The difference of squares states that for any two perfect squares A^2 and B^2, the expression A^2 - B^2 can be factored as (A + B)(A - B).

In our case, A^2 is equal to (3x)^2 and B^2 is equal to (4)^2.

So, let's apply the difference of squares to our expression:

9x^2 - 16 = (3x)^2 - 4^2

Now, we can rewrite the expression as follows:

9x^2 - 16 = (3x + 4)(3x - 4)

Therefore, the factored form of 9x^2-16 is (3x+4)(3x-4).