The table shows the cost of different tickets at a festival.
Child=$3
Adult=$5
Senior=$2
The Delgao family paid $20 for 6 tickets.If 2 of the tickets were senior tickets,then what might the other 4 tickets have been?
A.3adult and 1child
B.4child
C.2adult and 2 child
D.1adult and 3 child
C?
Right, again! :-)
To solve this problem, you can use trial and error by checking each option to see if it satisfies the given conditions.
Let's go through each option:
A. 3 adults and 1 child:
In this case, the cost would be (3 * $5) + (1 * $3) = $15 + $3 = $18. Therefore, this option does not satisfy the condition that the Delgao family paid $20.
B. 4 children:
In this case, the cost would be 4 * $3 = $12. Therefore, this option does not satisfy the condition that the Delgao family paid $20.
C. 2 adults and 2 children:
In this case, the cost would be (2 * $5) + (2 * $3) = $10 + $6 = $16. Therefore, this option does not satisfy the condition that the Delgao family paid $20.
D. 1 adult and 3 children:
In this case, the cost would be (1 * $5) + (3 * $3) = $5 + $9 = $14. Therefore, this option does not satisfy the condition that the Delgao family paid $20.
Since none of the given options satisfy the condition, we can conclude that there might be a mistake in the options provided.