A 2.5 L volume of sodium hydroxide solution was prepared. The titrant was standarized against primary standard oxalic acid dihydrate, H2C2O4*H2O(molar mass is 126.06) if a 0.4774g sample of the prmiary standard consumed 31.94mL of the base solution in reaching the phenophtalein end point, how many grams of sodium hydroxide were required to prepare the 2.5L of solution?

Question

A 2.5 L volume of sodium hydroxide solution was prepared. The titrant was standarized against primary standard oxalic acid dihydrate, H2C2O4*H2O(molar mass is 126.06) if a 0.4774g sample of the prmiary standard consumed 31.94mL of the base solution in reaching the phenophtalein end point, how many grams of sodium hydroxide were required to prepare the 2.5L of solution?

2NaOh(aq)+H2C2O4==>2H2O(l)+Na2C2O4)(aq)

Answer 1

H2Ox + 2NaOH ==> Na2Ox + 2H2O

mols Ox = grams/molar mass
mols NaOH required = 2 x mols Ox (from th equation).

M NaOH = mols NaOH/L NaOH/

Then to prepare 2.5L of solution you will need how many mols total? That is M x L = ?
grams NaOH = mols NaOH/molar mass NaOH. You know molar mass and mols, solve for grams.

Answer 2

To solve this problem, we first need to calculate the molarity of the oxalic acid dihydrate solution using the given information.

1. Calculate the number of moles of oxalic acid dihydrate:
Mass of oxalic acid dihydrate = 0.4774 g
Molar mass of oxalic acid dihydrate = 126.06 g/mol

Moles of oxalic acid dihydrate = mass / molar mass
Moles = 0.4774 g / 126.06 g/mol

2. Calculate the molarity of oxalic acid dihydrate solution:
Volume of oxalic acid dihydrate solution = 31.94 mL = 0.03194 L

Molarity (M) = moles / volume
Molarity = (0.4774 g / 126.06 g/mol) / 0.03194 L

Now that we have the molarity of the oxalic acid dihydrate solution, we can use it to determine the grams of sodium hydroxide required to prepare the 2.5 L solution.

3. Calculate the moles of sodium hydroxide:
Balanced equation: 2NaOH(aq) + H2C2O4(aq) → 2H2O(l) + Na2C2O4(aq)
According to the equation, the mole ratio of NaOH to H2C2O4 is 2:1.

Moles of NaOH = (2/1) * Moles of H2C2O4

4. Calculate the grams of sodium hydroxide:
Volume of sodium hydroxide solution = 2.5 L
Molarity of sodium hydroxide solution = molarity calculated for H2C2O4

Moles of NaOH = (Molarity of NaOH) * (Volume of NaOH solution)
Grams of NaOH = moles * molar mass of NaOH

Finally, calculate the grams of sodium hydroxide required for the 2.5 L solution using the molarity of the NaOH solution obtained from the titration.

Please substitute the values into the equations to find the result.