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A Student Performing a lab weighed a 1.0993g sample, containing an unknown KHP, which required 18.06mL of 0.1879M NAOH to reach the phenolphtalein endpoint.

a) How many moles of base were consumed by the KHP in this sample?
b) How many grams of KHP were titrated?
c)What is the mass percent of KHP in the sample?

  • Chemistry -

    mols NaOH = M x L = ?
    mols KHP = same (1:1 ratio) from
    KHP + NaOH ==> KNaP + H2O.

    Calculate mass KHP from g = mols x molar mass.

    Then %KHP = (mass KHP/mass sample)*100 = ?

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