Posted by **ed** on Tuesday, May 8, 2012 at 8:42pm.

the volume of a gas was originally 2.5 L; it's pressurewas 104kpa and its temperatire was 270K. the volume of the gas expanded to 5.3 L and its pressure decreased to 95 kpa. What is the temperature of the gas?

- chemistry -
**DrBob222**, Tuesday, May 8, 2012 at 8:47pm
(P1V1/T1) (P2V2/T2)

T must be in kelvin.

- chemistry -
**Jai**, Tuesday, May 8, 2012 at 8:56pm
For an ideal gas,

(P1*V1)/(T1) = (P2*V2)/(T2)

where

P1, V1 and T1 are the pressure, volume and temp at initial conditions, and

P2, V2 and T2 are the final conditions

Substituting,

(104*2.5)/270 = (95*5.3)/(T2)

now solve for T2.

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