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Posted by on Tuesday, May 8, 2012 at 4:51pm.

Benzoic acid (C6H5COOH)is a monoprotic weak acid with Ka=6.30*10^-5. What is the pH of a solution of benzoic acid that is 0.559M and has 2.25*10^-2M NaOH added?

  • Chemistry - , Tuesday, May 8, 2012 at 5:33pm

    By adding NaOH you have formed a buffered solution. Take 1 L soln, so you have
    1000 x 0.559 M = 559 millimols PhCOOH.
    1000 x 0.0225M = 22.5 mmols NaOH

    .......PhCOOH + NaOH ==> PhCOONa + H2O
    initial..559................0........0
    added...........22.5...................
    change....-22.5..-22.5.....22.5
    equil....536.5...0..........22.5

    Use the Henderson-Hasselbalch equation and solve for pH.

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