Posted by Pippi on Tuesday, May 8, 2012 at 4:51pm.
By adding NaOH you have formed a buffered solution. Take 1 L soln, so you have
1000 x 0.559 M = 559 millimols PhCOOH.
1000 x 0.0225M = 22.5 mmols NaOH
.......PhCOOH + NaOH ==> PhCOONa + H2O
initial..559................0........0
added...........22.5...................
change....-22.5..-22.5.....22.5
equil....536.5...0..........22.5
Use the Henderson-Hasselbalch equation and solve for pH.
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