Posted by **ally** on Tuesday, May 8, 2012 at 1:18pm.

In the figure the coefficient of static friction between mass (MA) and the table is 0.40, whereas the coefficient of kinetic friction is 0.28 ?

part a) What minimum value of (MA) will keep the system from starting to move?

part b) What value of(MA) will keep the system moving at constant speed?

- physics -
**Elena**, Tuesday, May 8, 2012 at 1:35pm
Block on the table m(A) = m1,

block on the cord m2,

the coefficient of static friction is k1=0.4,

the coefficient of kinetic friction is k2 =0.28

(a)

Block A:

T = F(fr) = k1 •N = k(s) • m1 •g,

Block B: T = m2•g.

k1 • m1 •g= m2•g,

m1 = m2/k(s) = m2/0.4.

(b)

Block A:

T = F(fr) = k2 •N = k2 • m1 •g,

Block B:

T = m2•g.

k2• m1 •g= m2•g,

m1 = m2/k2 = m2/0.28.

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