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Math

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The mean of a set of normally distributed data is 550 and the standard deviation is 35.
What percent of the data is between 515 and 585?

  • Math - ,

    Normalize 515 and 585, namely
    z(515)=(515-550)/35=-1
    z(585)=(585-550)/35=1
    The percent is the difference of probabilities of one-tail z-values between -1 and +1. It should be a little less than 70%.

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