Posted by Lea on .
Test the significance of the correlation coefficient r at a=0.05 for the data below.
X values 59, 65, 73, 80, 89
Y values 97, 102, 110, 117, 125
A) Accept p=0 because 60.81<3.18
B) Reject p=0 because 61.13>3.18
C) Accept p=0 because 61.13<2.78
D) Reject p=0 because 60.81>2.78

stats 
MathGuru,
Using an online calculator with the following pairs:
5 data pairs (x,y):
( 59.0 , 97.0 ); ( 65.0 , 102. ); ( 73.0 , 110. ); ( 80.0 , 117. ); ( 89.0 , 125. );
Degrees of freedom = N (number of pairs)  2 = 3
Correlation coefficient r = 1.00
Check the appropriate table for degrees of freedom and the level of significance to determine whether or not to reject the null.