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Posted by on Monday, May 7, 2012 at 10:19pm.

The half life of phosphorus -32 is 14.3 days. What percentage of an original samples radioactivity remains after 57.2 days?

  • chemistry - , Monday, May 7, 2012 at 10:29pm

    k = 0.693/t1/2/sub>
    ln(No/N) = kt
    No = 100 (for convenience)
    N = ?
    t = 57.5 days
    k from above.
    Then (N/No)*100 = %remaining.

  • chemistry - , Wednesday, September 23, 2015 at 11:22pm

    Poooty butt

  • chemistry - , Wednesday, September 23, 2015 at 11:23pm

    potty butt

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