Homework Help: chemistry

Posted by matt on Monday, May 7, 2012 at 10:19pm.

The half life of phosphorus -32 is 14.3 days. What percentage of an original samples radioactivity remains after 57.2 days?

chemistry - DrBob222, Monday, May 7, 2012 at 10:29pm
k = 0.693/t_{1/2/sub>

ln(No/N) = kt

No = 100 (for convenience)

N = ?

t = 57.5 days

k from above.

Then (N/No)*100 = %remaining.}

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