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December 19, 2014

December 19, 2014

Posted by **jenny** on Monday, May 7, 2012 at 8:20pm.

Solve the system by elimination.

1)y=x^2+2

-4x-y=10

2) Solve the system using substitution.

Y=-3x^2+x-2

Y=-5x+3

- algebra 2 -
**Reiny**, Monday, May 7, 2012 at 8:35pm1)

add them the way they sit

-4x = x^2 + 12

x^2 + 4x + 12 = 0

I would complete the square:

x^2 + 4x + 4 = -12 + 4

(x+2)^2 = -8

x+2 = ± √-8 = ± 2√2 i

x = -2 ± 2√2 i

for 2)

you would get

-5x+3 = -3x^2 + x - 2

3x^2 - 6x + 5 = 0

give it a shot...... (use the formula)

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