Posted by Tom on Monday, May 7, 2012 at 5:06pm.
m•a = F
a = v^2/R is the normal (centripetal) acceleration,
F= q•v•B•sinα is Lorentz force , here, sinα = 1,
F =e•v•B,
e =1.6•10^-19 C is the charge of electrom,
m =9.1•10^-31 kg is the mass of electron.
m• v^2/R = e•v•B,
m• v/R = e•B,
R = m•v/e•B= =9.1•10^-31•150/1.6•10^-19•0.5= =1.71•10^-9 m.
The çath is the circle of ràdius
R = 1.71•10^-9 m.
If the electron moves to the left, and magnetic field points out of the page, the Lorentz force is directed downwards, therefore, the electron is rotating clockwise about the magnetic field lines.
Thanks Elena
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