Posted by NICOLE on Monday, May 7, 2012 at 4:19pm.
MgCO3 ==> Mg^2+ + CO3^2-
....x......x........x
where x = solubility in mols/L.
........MgCl2 --> Mg^2+ + 2Cl^-
I........0.65.....0..........0
C.......-0.65....0.65.....2*0.65
E .......0.........0.65....1.30
Substitute from the above ICE charts into Ksp for MgCO3 and solve for x.
(Mg^2+) = x+0.65 (that's x from MgCO3 and 0.65 from MgCl2.)
(CO3^2-) = x
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